2x^2-(x^2-8)=12

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Solution for 2x^2-(x^2-8)=12 equation: 


Simplifying
2x2 + -1(x2 + -8) = 12

Reorder the terms:
2x2 + -1(-8 + x2) = 12
2x2 + (-8 * -1 + x2 * -1) = 12
2x2 + (8 + -1x2) = 12

Reorder the terms:
8 + 2x2 + -1x2 = 12

Combine like terms: 2x2 + -1x2 = 1x2
8 + 1x2 = 12

Solving
8 + 1x2 = 12

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + 1x2 = 12 + -8

Combine like terms: 8 + -8 = 0
0 + 1x2 = 12 + -8
1x2 = 12 + -8

Combine like terms: 12 + -8 = 4
1x2 = 4

Divide each side by '1'.
x2 = 4

Simplifying
x2 = 4

Take the square root of each side:
x = {-2, 2}

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